# continue

Stopping a loop is great, but what if we would like to just skip this one time? What if we don’t want to execute the rest of the loop for this specific value, but want to keep the loop going?
To do that we can use the `continue` statement, which would continue the execution to the next round of the loop:
``````numbers = [1, 5, 6, 4, 0, -4, 8, 11, 2]
even_sum = 0
for n in numbers:
if n % 2 != 0:
continue
even_sum += n
print(n)

print('Sum:', even_sum)``````
``````6
4
0
-4
8
2
Sum: 16``````
This program will skip the execution for each `n` that `n % 2 != 0` (n is not even).
`continue` skips the execution of whatever comes after it. So, everything before `continue` is still getting executed. Python has to reach the statement `continue` to know that it needs to skip the rest.

#### Challenge

Given 10 integers, the program should print each number if all the conditions hold:
• It’s odd
• It lies outside the range `[3, 7]`
• It lies outside the range `[11, 13]`
• It lies outside the range `[17, 23]`
 Input Output 12 9 6 0 1 -1 41 28 27 17 9 1 -1 41 27
Note that `[l, r]` indicates the range from `l` to `r` where both `l` and `r` are inclusive.

#### Constraints

Time limit: 2 seconds

Memory limit: 512 MB

Output limit: 1 MB